Optimal. Leaf size=193 \[ i b c^2 d \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{1}{2} b^2 c^2 d \text{PolyLog}\left (3,e^{2 i \sin ^{-1}(c x)}\right )-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-c^2 d \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )^2+b^2 c^2 d \log (x) \]
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Rubi [A] time = 0.286697, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 10, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.4, Rules used = {4695, 4625, 3717, 2190, 2531, 2282, 6589, 4693, 29, 4641} \[ i b c^2 d \text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )-\frac{1}{2} b^2 c^2 d \text{PolyLog}\left (3,e^{2 i \sin ^{-1}(c x)}\right )-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-c^2 d \log \left (1-e^{2 i \sin ^{-1}(c x)}\right ) \left (a+b \sin ^{-1}(c x)\right )^2+b^2 c^2 d \log (x) \]
Antiderivative was successfully verified.
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Rule 4695
Rule 4625
Rule 3717
Rule 2190
Rule 2531
Rule 2282
Rule 6589
Rule 4693
Rule 29
Rule 4641
Rubi steps
\begin{align*} \int \frac{\left (d-c^2 d x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{x^3} \, dx &=-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+(b c d) \int \frac{\sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x^2} \, dx-\left (c^2 d\right ) \int \frac{\left (a+b \sin ^{-1}(c x)\right )^2}{x} \, dx\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}-\left (c^2 d\right ) \operatorname{Subst}\left (\int (a+b x)^2 \cot (x) \, dx,x,\sin ^{-1}(c x)\right )+\left (b^2 c^2 d\right ) \int \frac{1}{x} \, dx-\left (b c^3 d\right ) \int \frac{a+b \sin ^{-1}(c x)}{\sqrt{1-c^2 x^2}} \, dx\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}+b^2 c^2 d \log (x)+\left (2 i c^2 d\right ) \operatorname{Subst}\left (\int \frac{e^{2 i x} (a+b x)^2}{1-e^{2 i x}} \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-c^2 d \left (a+b \sin ^{-1}(c x)\right )^2 \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+b^2 c^2 d \log (x)+\left (2 b c^2 d\right ) \operatorname{Subst}\left (\int (a+b x) \log \left (1-e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-c^2 d \left (a+b \sin ^{-1}(c x)\right )^2 \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+b^2 c^2 d \log (x)+i b c^2 d \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )-\left (i b^2 c^2 d\right ) \operatorname{Subst}\left (\int \text{Li}_2\left (e^{2 i x}\right ) \, dx,x,\sin ^{-1}(c x)\right )\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-c^2 d \left (a+b \sin ^{-1}(c x)\right )^2 \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+b^2 c^2 d \log (x)+i b c^2 d \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )-\frac{1}{2} \left (b^2 c^2 d\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{2 i \sin ^{-1}(c x)}\right )\\ &=-\frac{b c d \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{x}-\frac{1}{2} c^2 d \left (a+b \sin ^{-1}(c x)\right )^2-\frac{d \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2}{2 x^2}+\frac{i c^2 d \left (a+b \sin ^{-1}(c x)\right )^3}{3 b}-c^2 d \left (a+b \sin ^{-1}(c x)\right )^2 \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )+b^2 c^2 d \log (x)+i b c^2 d \left (a+b \sin ^{-1}(c x)\right ) \text{Li}_2\left (e^{2 i \sin ^{-1}(c x)}\right )-\frac{1}{2} b^2 c^2 d \text{Li}_3\left (e^{2 i \sin ^{-1}(c x)}\right )\\ \end{align*}
Mathematica [A] time = 0.392648, size = 236, normalized size = 1.22 \[ \frac{1}{2} d \left (2 i a b c^2 \left (\text{PolyLog}\left (2,e^{2 i \sin ^{-1}(c x)}\right )+\sin ^{-1}(c x) \left (\sin ^{-1}(c x)+2 i \log \left (1-e^{2 i \sin ^{-1}(c x)}\right )\right )\right )+\frac{1}{12} i b^2 c^2 \left (-24 \sin ^{-1}(c x) \text{PolyLog}\left (2,e^{-2 i \sin ^{-1}(c x)}\right )+12 i \text{PolyLog}\left (3,e^{-2 i \sin ^{-1}(c x)}\right )-8 \sin ^{-1}(c x)^3+24 i \sin ^{-1}(c x)^2 \log \left (1-e^{-2 i \sin ^{-1}(c x)}\right )+\pi ^3\right )-2 a^2 c^2 \log (x)-\frac{a^2}{x^2}-\frac{2 a b \left (c x \sqrt{1-c^2 x^2}+\sin ^{-1}(c x)\right )}{x^2}-\frac{b^2 \left (-2 c^2 x^2 \log (c x)+2 c x \sqrt{1-c^2 x^2} \sin ^{-1}(c x)+\sin ^{-1}(c x)^2\right )}{x^2}\right ) \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.337, size = 564, normalized size = 2.9 \begin{align*} -{\frac{d{a}^{2}}{2\,{x}^{2}}}-{c}^{2}d{a}^{2}\ln \left ( cx \right ) +i{c}^{2}dab+2\,i{c}^{2}dab{\it polylog} \left ( 2,-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) -{\frac{dc{b}^{2}\arcsin \left ( cx \right ) }{x}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{d{b}^{2} \left ( \arcsin \left ( cx \right ) \right ) ^{2}}{2\,{x}^{2}}}-{c}^{2}d{b}^{2} \left ( \arcsin \left ( cx \right ) \right ) ^{2}\ln \left ( 1+icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) +2\,i{c}^{2}d{b}^{2}\arcsin \left ( cx \right ){\it polylog} \left ( 2,-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) -2\,{c}^{2}d{b}^{2}{\it polylog} \left ( 3,-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) -{c}^{2}d{b}^{2} \left ( \arcsin \left ( cx \right ) \right ) ^{2}\ln \left ( 1-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) +i{c}^{2}d{b}^{2}\arcsin \left ( cx \right ) -2\,{c}^{2}d{b}^{2}{\it polylog} \left ( 3,icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) +{c}^{2}d{b}^{2}\ln \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1}-1 \right ) +{c}^{2}d{b}^{2}\ln \left ( 1+icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) -2\,{c}^{2}d{b}^{2}\ln \left ( icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) +i{c}^{2}dab \left ( \arcsin \left ( cx \right ) \right ) ^{2}+2\,i{c}^{2}dab{\it polylog} \left ( 2,icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) -{\frac{dcab}{x}\sqrt{-{c}^{2}{x}^{2}+1}}-{\frac{dab\arcsin \left ( cx \right ) }{{x}^{2}}}-2\,{c}^{2}dab\arcsin \left ( cx \right ) \ln \left ( 1+icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) -2\,{c}^{2}dab\arcsin \left ( cx \right ) \ln \left ( 1-icx-\sqrt{-{c}^{2}{x}^{2}+1} \right ) +{\frac{i}{3}}{c}^{2}d{b}^{2} \left ( \arcsin \left ( cx \right ) \right ) ^{3}+2\,i{c}^{2}d{b}^{2}\arcsin \left ( cx \right ){\it polylog} \left ( 2,icx+\sqrt{-{c}^{2}{x}^{2}+1} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -a^{2} c^{2} d \log \left (x\right ) - a b d{\left (\frac{\sqrt{-c^{2} x^{2} + 1} c}{x} + \frac{\arcsin \left (c x\right )}{x^{2}}\right )} - \frac{a^{2} d}{2 \, x^{2}} - \int \frac{2 \, a b c^{2} d x^{2} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right ) +{\left (b^{2} c^{2} d x^{2} - b^{2} d\right )} \arctan \left (c x, \sqrt{c x + 1} \sqrt{-c x + 1}\right )^{2}}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{a^{2} c^{2} d x^{2} - a^{2} d +{\left (b^{2} c^{2} d x^{2} - b^{2} d\right )} \arcsin \left (c x\right )^{2} + 2 \,{\left (a b c^{2} d x^{2} - a b d\right )} \arcsin \left (c x\right )}{x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - d \left (\int - \frac{a^{2}}{x^{3}}\, dx + \int \frac{a^{2} c^{2}}{x}\, dx + \int - \frac{b^{2} \operatorname{asin}^{2}{\left (c x \right )}}{x^{3}}\, dx + \int - \frac{2 a b \operatorname{asin}{\left (c x \right )}}{x^{3}}\, dx + \int \frac{b^{2} c^{2} \operatorname{asin}^{2}{\left (c x \right )}}{x}\, dx + \int \frac{2 a b c^{2} \operatorname{asin}{\left (c x \right )}}{x}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (c^{2} d x^{2} - d\right )}{\left (b \arcsin \left (c x\right ) + a\right )}^{2}}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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